Module clpz
:- use_module(library(clpz)).
Constraint Logic Programming over Integers
Introduction
This library provides CLP(ℤ): Constraint Logic Programming over Integers.
CLP(ℤ) is an instance of the general CLP(X) scheme, extending logic programming with reasoning over specialised domains. CLP(ℤ) lets us reason about integers in a way that honors the relational nature of Prolog.
There are two major use cases of CLP(ℤ) constraints:
solving combinatorial problems such as planning, scheduling and allocation tasks.
The predicates of this library can be classified as:
arithmetic constraints like
(#=)/2
,(#>)/2
and(#\=)/2
the membership constraints
(in)/2
and(ins)/2
the enumeration predicates
indomain/1
,label/1
andlabeling/2
combinatorial constraints like
all_distinct/1
andglobal_cardinality/2
reification predicates such as
(#<==>)/2
reflection predicates such as
fd_dom/2
In most cases, arithmetic constraints are the only predicates you will ever need from this library. When reasoning over integers, simply replace low-level arithmetic predicates like (is)/2
and (>)/2
by the corresponding CLP(ℤ) constraints like (#=)/2
and (#>)/2
to honor and preserve declarative properties of your programs. For satisfactory performance, arithmetic constraints are implicitly rewritten at compilation time so that low-level fallback predicates are automatically used whenever possible.
Almost all Prolog programs also reason about integers. Therefore, it is highly advisable that you make CLP(ℤ) constraints available in all your programs. One way to do this is to put the following directive in your ~/.scryerrc
initialisation file:
:- use_module(library(clpz)).
All example programs that appear in the CLP(ℤ) documentation assume that you have done this.
Important concepts and principles of this library are illustrated by means of usage examples that are available in a public git repository: https://github.com/triska/clpz
If you are used to the complicated operational considerations that low-level arithmetic primitives necessitate, then moving to CLP(ℤ) constraints may, due to their power and convenience, at first feel to you excessive and almost like cheating. It isn't. Constraints are an integral part of all popular Prolog systems, and they are designed to help you eliminate and avoid the use of low-level and less general primitives by providing declarative alternatives that are meant to be used instead.
When teaching Prolog, CLP(ℤ) constraints should be introduced before explaining low-level arithmetic predicates and their procedural idiosyncrasies. This is because constraints are easy to explain, understand and use due to their purely relational nature. In contrast, the modedness and directionality of low-level arithmetic primitives are impure limitations that are better deferred to more advanced lectures.
More information about CLP(ℤ) constraints and their implementation is contained in: metalevel.at/drt.pdf
The best way to discuss applying, improving and extending CLP(ℤ) constraints is to use the dedicated clpz
tag on stackoverflow.com. Several of the world's foremost CLP(ℤ) experts regularly participate in these discussions and will help you for free on this platform.
Arithmetic constraints
In modern Prolog systems, arithmetic constraints subsume and supersede low-level predicates over integers. The main advantage of arithmetic constraints is that they are true relations and can be used in all directions. For most programs, arithmetic constraints are the only predicates you will ever need from this library.
The most important arithmetic constraint is (#=)/2
, which subsumes both (is)/2
and (=:=)/2
over integers. Use (#=)/2
to make your programs more general.
In total, the arithmetic constraints are:
Expr1 #= Expr2 | Expr1 equals Expr2 |
Expr1 #\= Expr2 | Expr1 is not equal to Expr2 |
Expr1 #>= Expr2 | Expr1 is greater than or equal to Expr2 |
Expr1 #=< Expr2 | Expr1 is less than or equal to Expr2 |
Expr1 #> Expr2 | Expr1 is greater than Expr2 |
Expr1 #< Expr2 | Expr1 is less than Expr2 |
Expr1
and Expr2
denote arithmetic expressions, which are:
integer | Given value |
variable | Unknown integer |
#(variable) | Unknown integer |
-Expr | Unary minus |
Expr + Expr | Addition |
Expr * Expr | Multiplication |
Expr - Expr | Subtraction |
Expr ^ Expr | Exponentiation |
min(Expr,Expr) | Minimum of two expressions |
max(Expr,Expr) | Maximum of two expressions |
Expr mod Expr | Modulo induced by floored division |
Expr rem Expr | Modulo induced by truncated division |
abs(Expr) | Absolute value |
sign(Expr) | Sign (-1, 0, 1) of Expr |
Expr // Expr | Truncated integer division |
Expr div Expr | Floored integer division |
where Expr
again denotes an arithmetic expression.
The bitwise operations (\)/1
, (/\)/2
, (\/)/2
, (>>)/2
, (<<)/2
, lsb/1
, msb/1
, popcount/1
and (xor)/2
are also supported.
Declarative integer arithmetic
The arithmetic constraints (#=)/2
, (#>)/2
etc. are meant to be used instead of the primitives (is)/2
, (=:=)/2
, (>)/2
etc. over integers. Almost all Prolog programs also reason about integers. Therefore, it is recommended that you put the following directive in your ~/.scryerrc
initialisation file to make CLP(ℤ) constraints available in all your programs:
:- use_module(library(clpz)).
Throughout the following, it is assumed that you have done this.
The most basic use of CLP(ℤ) constraints is evaluation of arithmetic expressions involving integers. For example:
?- X #= 1+2.
X = 3.
This could in principle also be achieved with the lower-level predicate (is)/2
. However, an important advantage of arithmetic constraints is their purely relational nature: Constraints can be used in all directions, also if one or more of their arguments are only partially instantiated. For example:
?- 3 #= Y+2.
Y = 1.
This relational nature makes CLP(ℤ) constraints easy to explain and use, and well suited for beginners and experienced Prolog programmers alike. In contrast, when using low-level integer arithmetic, we get:
?- 3 is Y+2.
error(instantiation_error,(is)/2).
?- 3 =:= Y+2.
error(instantiation_error,(is)/2).
Due to the necessary operational considerations, the use of these low-level arithmetic predicates is considerably harder to understand and should therefore be deferred to more advanced lectures.
For supported expressions, CLP(ℤ) constraints are drop-in replacements of these low-level arithmetic predicates, often yielding more general programs. See n_factorial/2
for an example.
This library uses goalexpansion/2 to automatically rewrite constraints at compilation time so that low-level arithmetic predicates are _automatically used whenever possible. For example, the predicate:
positive_integer(N) :- N #>= 1.
is executed as if it were written as:
positive_integer(N) :-
( integer(N)
-> N >= 1
; N #>= 1
).
This illustrates why the performance of CLP(ℤ) constraints is almost always completely satisfactory when they are used in modes that can be handled by low-level arithmetic. To disable the automatic rewriting, set the Prolog flag clpz_goal_expansion
to false
.
If you are used to the complicated operational considerations that low-level arithmetic primitives necessitate, then moving to CLP(ℤ) constraints may, due to their power and convenience, at first feel to you excessive and almost like cheating. It isn't. Constraints are an integral part of all popular Prolog systems, and they are designed to help you eliminate and avoid the use of low-level and less general primitives by providing declarative alternatives that are meant to be used instead.
Example: Factorial relation
We illustrate the benefit of using (#=)/2
for more generality with a simple example.
Consider first a rather conventional definition of n_factorial/2
, relating each natural number N to its factorial F:
n_factorial(0, 1).
n_factorial(N, F) :-
N #> 0,
N1 #= N - 1,
n_factorial(N1, F1),
F #= N * F1.
This program uses CLP(ℤ) constraints instead of low-level arithmetic throughout, and everything that would have worked with low-level arithmetic also works with CLP(ℤ) constraints, retaining roughly the same performance. For example:
?- n_factorial(47, F).
F = 258623241511168180642964355153611979969197632389120000000000
; false.
Now the point: Due to the increased flexibility and generality of CLP(ℤ) constraints, we are free to reorder the goals as follows:
n_factorial(0, 1).
n_factorial(N, F) :-
N #> 0,
N1 #= N - 1,
F #= N * F1,
n_factorial(N1, F1).
In this concrete case, termination properties of the predicate are improved. For example, the following queries now both terminate:
?- n_factorial(N, 1).
N = 0
; N = 1
; false.
?- n_factorial(N, 3).
false.
To make the predicate terminate if any argument is instantiated, add the (implied) constraint F #\= 0
before the recursive call. Otherwise, the query n_factorial(N, 0)
is the only non-terminating case of this kind.
The value of CLP(ℤ) constraints does not lie in completely freeing us from all procedural phenomena. For example, the two programs do not even have the same termination properties in all cases. Instead, the primary benefit of CLP(ℤ) constraints is that they allow you to try different execution orders and apply declarative debugging techniques at all! Reordering goals (and clauses) can significantly impact the performance of Prolog programs, and you are free to try different variants if you use declarative approaches. Moreover, since all CLP(ℤ) constraints always terminate, placing them earlier can at most improve, never worsen, the termination properties of your programs. An additional benefit of CLP(ℤ) constraints is that they eliminate the complexity of introducing (is)/2
and (=:=)/2
to beginners, since both predicates are subsumed by (#=)/2
when reasoning over integers.
Combinatorial constraints
In addition to subsuming and replacing low-level arithmetic predicates, CLP(ℤ) constraints are often used to solve combinatorial problems such as planning, scheduling and allocation tasks. Among the most frequently used combinatorial constraints are all_distinct/1
, global_cardinality/2
and cumulative/2
. This library also provides several other constraints like disjoint2/1
and automaton/8
, which are useful in more specialized applications.
Domains
Each CLP(ℤ) variable has an associated set of admissible integers, which we call the variable's domain. Initially, the domain of each CLP(ℤ) variable is the set of all integers. CLP(ℤ) constraints like (#=)/2
, (#>)/2
and (#\=)/2
can at most reduce, and never extend, the domains of their arguments. The constraints (in)/2
and (ins)/2
let us explicitly state domains of CLP(ℤ) variables. The process of determining and adjusting domains of variables is called constraint propagation, and it is performed automatically by this library. When the domain of a variable contains only one element, then the variable is automatically unified to that element.
Domains are taken into account when further constraints are stated, and by enumeration predicates like labeling/2.
Example: Sudoku
As another example, consider Sudoku: It is a popular puzzle over integers that can be easily solved with CLP(ℤ) constraints.
sudoku(Rows) :-
length(Rows, 9), maplist(same_length(Rows), Rows),
append(Rows, Vs), Vs ins 1..9,
maplist(all_distinct, Rows),
transpose(Rows, Columns),
maplist(all_distinct, Columns),
Rows = [As,Bs,Cs,Ds,Es,Fs,Gs,Hs,Is],
blocks(As, Bs, Cs),
blocks(Ds, Es, Fs),
blocks(Gs, Hs, Is).
blocks([], [], []).
blocks([N1,N2,N3|Ns1], [N4,N5,N6|Ns2], [N7,N8,N9|Ns3]) :-
all_distinct([N1,N2,N3,N4,N5,N6,N7,N8,N9]),
blocks(Ns1, Ns2, Ns3).
problem(1, [[_,_,_,_,_,_,_,_,_],
[_,_,_,_,_,3,_,8,5],
[_,_,1,_,2,_,_,_,_],
[_,_,_,5,_,7,_,_,_],
[_,_,4,_,_,_,1,_,_],
[_,9,_,_,_,_,_,_,_],
[5,_,_,_,_,_,_,7,3],
[_,_,2,_,1,_,_,_,_],
[_,_,_,_,4,_,_,_,9]]).
Sample query:
?- problem(1, Rows), sudoku(Rows), maplist(portray_clause, Rows).
[9,8,7,6,5,4,3,2,1].
[2,4,6,1,7,3,9,8,5].
[3,5,1,9,2,8,7,4,6].
[1,2,8,5,3,7,6,9,4].
[6,3,4,8,9,2,1,5,7].
[7,9,5,4,6,1,8,3,2].
[5,1,9,2,8,6,4,7,3].
[4,7,2,3,1,9,5,6,8].
[8,6,3,7,4,5,2,1,9].
Rows = [[9,8,7,6,5,4,3,2,1]|...].
In this concrete case, the constraint solver is strong enough to find the unique solution without any search.
Residual goals
Here is an example session with a few queries and their answers:
?- X #> 3.
clpz:(X in 4..sup).
?- X #\= 20.
clpz:(X in inf..19\/21..sup).
?- 2*X #= 10.
X = 5.
?- X*X #= 144.
clpz:(X in-12\/12)
; false.
?- 4*X + 2*Y #= 24, X + Y #= 9, [X,Y] ins 0..sup.
X = 3, Y = 6.
?- X #= Y #<==> B, X in 0..3, Y in 4..5.
B = 0, clpz:(X in 0..3), clpz:(Y in 4..5).
The answers emitted by the toplevel are called residual programs, and the goals that comprise each answer are called residual goals. In each case above, and as for all pure programs, the residual program is declaratively equivalent to the original query. From the residual goals, it is clear that the constraint solver has deduced additional domain restrictions in many cases.
To inspect residual goals, it is best to let the toplevel display them for us. Wrap the call of your predicate into call_residue_vars/2
to make sure that all constrained variables are displayed. To make the constraints a variable is involved in available as a Prolog term for further reasoning within your program, use copy_term/3
. For example:
?- X #= Y + Z, X in 0..5, copy_term([X,Y,Z], [X,Y,Z], Gs).
Gs = [clpz: (X in 0..5), clpz: (Y+Z#=X)],
X in 0..5,
Y+Z#=X.
This library also provides reflection predicates (like fd_dom/2
, fd_size/2
etc.) with which we can inspect a variable's current domain. These predicates can be useful if you want to implement your own labeling strategies.
Core relations and search
Using CLP(ℤ) constraints to solve combinatorial tasks typically consists of two phases:
First, all relevant constraints are stated.
Second, if the domain of each involved variable is finite, then enumeration predicates can be used to search for concrete solutions.
It is good practice to keep the modeling part, via a dedicated predicate called the core relation, separate from the actual search for solutions. This lets us observe termination and determinism properties of the core relation in isolation from the search, and more easily try different search strategies.
As an example of a constraint satisfaction problem, consider the cryptoarithmetic puzzle SEND + MORE = MONEY, where different letters denote distinct integers between 0 and 9. It can be modeled in CLP(ℤ) as follows:
puzzle([S,E,N,D] + [M,O,R,E] = [M,O,N,E,Y]) :-
Vars = [S,E,N,D,M,O,R,Y],
Vars ins 0..9,
all_different(Vars),
S*1000 + E*100 + N*10 + D +
M*1000 + O*100 + R*10 + E #=
M*10000 + O*1000 + N*100 + E*10 + Y,
M #\= 0, S #\= 0.
Notice that we are not using labeling/2
in this predicate, so that we can first execute and observe the modeling part in isolation. Sample query and its result (actual variables replaced for readability):
?- puzzle(As+Bs=Cs).
As = [9, A2, A3, A4],
Bs = [1, 0, B3, A2],
Cs = [1, 0, A3, A2, C5],
A2 in 4..7,
all_different([9, A2, A3, A4, 1, 0, B3, C5]),
91*A2+A4+10*B3#=90*A3+C5,
A3 in 5..8,
A4 in 2..8,
B3 in 2..8,
C5 in 2..8.
From this answer, we see that this core relation terminates and is in fact deterministic. Moreover, we see from the residual goals that the constraint solver has deduced more stringent bounds for all variables. Such observations are only possible if modeling and search parts are cleanly separated.
Labeling can then be used to search for solutions in a separate predicate or goal:
?- puzzle(As+Bs=Cs), label(As).
As = [9,5,6,7], Bs = [1,0,8,5], Cs = [1,0,6,5,2]
; false.
In this case, it suffices to label a subset of variables to find the puzzle's unique solution, since the constraint solver is strong enough to reduce the domains of remaining variables to singleton sets. In general though, it is necessary to label all variables to obtain ground solutions.
Example: Eight queens puzzle
We illustrate the concepts of the preceding sections by means of the so-called eight queens puzzle. The task is to place 8 queens on an 8x8 chessboard such that none of the queens is under attack. This means that no two queens share the same row, column or diagonal.
To express this puzzle via CLP(ℤ) constraints, we must first pick a suitable representation. Since CLP(ℤ) constraints reason over integers, we must find a way to map the positions of queens to integers. Several such mappings are conceivable, and it is not immediately obvious which we should use. On top of that, different constraints can be used to express the desired relations. For such reasons, modeling combinatorial problems via CLP(ℤ) constraints often necessitates some creativity and has been described as more of an art than a science.
In our concrete case, we observe that there must be exactly one queen per column. The following representation therefore suggests itself: We are looking for 8 integers, one for each column, where each integer denotes the row of the queen that is placed in the respective column, and which are subject to certain constraints.
In fact, let us now generalize the task to the so-called N queens puzzle, which is obtained by replacing 8 by N everywhere it occurs in the above description. We implement the above considerations in the core relation n_queens/2
, where the first argument is the number of queens (which is identical to the number of rows and columns of the generalized chessboard), and the second argument is a list of N integers that represents a solution in the form described above.
n_queens(N, Qs) :-
length(Qs, N),
Qs ins 1..N,
safe_queens(Qs).
safe_queens([]).
safe_queens([Q|Qs]) :- safe_queens(Qs, Q, 1), safe_queens(Qs).
safe_queens([], _, _).
safe_queens([Q|Qs], Q0, D0) :-
Q0 #\= Q,
abs(Q0 - Q) #\= D0,
D1 #= D0 + 1,
safe_queens(Qs, Q0, D1).
Note that all these predicates can be used in all directions: We can use them to find solutions, test solutions and complete partially instantiated solutions.
The original task can be readily solved with the following query:
?- n_queens(8, Qs), label(Qs).
Qs = [1,5,8,6,3,7,2,4]
; ... .
Using suitable labeling strategies, we can easily find solutions with 80 queens and more:
?- n_queens(80, Qs), labeling([ff], Qs).
Qs = [1,3,5,44,42,4,50,7,68,57,76,61,6,39,30,40,8,54,36,41|...]
; ... .
?- time((n_queens(90, Qs), labeling([ff], Qs))).
% CPU time: 2.382s
Qs = [1,3,5,50,42,4,49,7,59,48,46,63,6,55,47,64,8,70,58,67|...]
; ... .
Experimenting with different search strategies is easy because we have separated the core relation from the actual search.
Optimisation
We can use labeling/2
to minimize or maximize the value of a CLP(ℤ) expression, and generate solutions in increasing or decreasing order of the value. See the labeling options min(Expr)
and max(Expr)
, respectively.
Again, to easily try different labeling options in connection with optimisation, we recommend to introduce a dedicated predicate for posting constraints, and to use labeling/2
in a separate goal. This way, we can observe properties of the core relation in isolation, and try different labeling options without recompiling our code.
If necessary, we can use once/1
to commit to the first optimal solution. However, it is often very valuable to see alternative solutions that are also optimal, so that we can choose among optimal solutions by other criteria. For the sake of purity and completeness, we recommend to avoid once/1
and other constructs that lead to impurities in CLP(ℤ) programs.
Related to optimisation with CLP(ℤ) constraints are library(simplex)
and CLP(Q) which reason about linear constraints over rational numbers.
Reification
The constraints (in)/2
, (#=)/2
, (#\=)/2
, (#<)/2
, (#>)/2
, (#=<)/2
, and (#>=)/2
can be reified, which means reflecting their truth values into Boolean values represented by the integers 0 and 1. Let P and Q denote reifiable constraints or Boolean variables, then:
#\ Q | True iff Q is false |
P #\/ Q | True iff either P or Q |
P #/\ Q | True iff both P and Q |
P #\ Q | True iff either P or Q, but not both |
P #<==> Q | True iff P and Q are equivalent |
P #==> Q | True iff P implies Q |
P #<== Q | True iff Q implies P |
The constraints of this table are reifiable as well.
When reasoning over Boolean variables, also consider using CLP(B) constraints as provided by library(clpb)
.
Enabling monotonic CLP(ℤ)
In the default execution mode, CLP(ℤ) constraints still exhibit some non-relational properties. For example, adding constraints can yield new solutions:
?- X #= 2, X = 1+1.
false.
?- X = 1+1, X #= 2, X = 1+1.
X = 1+1.
This behaviour is highly problematic from a logical point of view, and it may render declarative debugging techniques inapplicable.
Assert clpz:monotonic
to make CLP(ℤ) monotonic: This means that adding new constraints cannot yield new solutions. When this flag is true
, we must wrap variables that occur in arithmetic expressions with the functor (?)/1
or (#)/1
. For example:
?- assertz(clpz:monotonic).
true.
?- #X #= #Y + #Z.
clpz:(#Y+ #Z#= #X).
?- X #= 2, X = 1+1.
error(instantiation_error,instantiation_error(unknown(_408),1)).
The wrapper can be omitted for variables that are already constrained to integers.
Custom constraints
We can define custom constraints. The mechanism to do this is not yet finalised, and we welcome suggestions and descriptions of use cases that are important to you.
As an example of how it can be done currently, let us define a new custom constraint oneground(X,Y,Z)
, where Z shall be 1 if at least one of X and Y is instantiated:
:- multifile clpz:run_propagator/2.
oneground(X, Y, Z) :-
clpz:make_propagator(oneground(X, Y, Z), Prop),
clpz:init_propagator(X, Prop),
clpz:init_propagator(Y, Prop),
clpz:trigger_once(Prop).
clpz:run_propagator(oneground(X, Y, Z), MState) :-
( integer(X) -> clpz:kill(MState), Z = 1
; integer(Y) -> clpz:kill(MState), Z = 1
; true
).
First, clpz:make_propagator/2
is used to transform a user-defined representation of the new constraint to an internal form. With clpz:init_propagator/2
, this internal form is then attached to X and Y. From now on, the propagator will be invoked whenever the domains of X or Y are changed. Then, clpz:trigger_once/1
is used to give the propagator its first chance for propagation even though the variables' domains have not yet changed. Finally, clpz:run_propagator/2
is extended to define the actual propagator. As explained, this predicate is automatically called by the constraint solver. The first argument is the user-defined representation of the constraint as used in clpz:make_propagator/2
, and the second argument is a mutable state that can be used to prevent further invocations of the propagator when the constraint has become entailed, by using clpz:kill/1
. An example of using the new constraint:
?- oneground(X, Y, Z), Y = 5.
Y = 5,
Z = 1,
X in inf..sup.
@author Markus Triska
in(?Var, +Domain)
Var is an element of Domain. Domain is one of:
- Integer Singleton set consisting only of Integer.
- Lower..Upper All integers I such that Lower =< I =< Upper. Lower must be an integer or the atom inf, which denotes negative infinity. Upper must be an integer or the atom sup, which denotes positive infinity.
- Domain1
\/
Domain2 The union of Domain1 and Domain2.
ins(+Vars, +Domain)
The variables in the list Vars are elements of Domain.
indomain(?Var)
Bind Var to all feasible values of its domain on backtracking. The domain of Var must be finite.
label(+Vars)
Equivalent to labeling([], Vars).
labeling(+Options, +Vars)
Assign a value to each variable in Vars. Labeling means systematically trying out values for the finite domain variables Vars until all of them are ground. The domain of each variable in Vars must be finite. Options is a list of options that let you exhibit some control over the search process. Several categories of options exist:
The variable selection strategy lets you specify which variable of Vars is labeled next and is one of:
leftmost Label the variables in the order they occur in Vars. This is the default.
ff |First fail|. Label the leftmost variable with smallest domain next, in order to detect infeasibility early. This is often a good strategy.
ffc Of the variables with smallest domains, the leftmost one participating in most constraints is labeled next.
min Label the leftmost variable whose lower bound is the lowest next.
max Label the leftmost variable whose upper bound is the highest next.
The value order is one of:
up Try the elements of the chosen variable's domain in ascending order. This is the default.
down Try the domain elements in descending order.
The branching strategy is one of:
step For each variable X, a choice is made between X = V and X #= V, where V is determined by the value ordering options. This is the default.
enum For each variable X, a choice is made between X = V1, X = V2 etc., for all values V_i of the domain of X. The order is determined by the value ordering options.
bisect For each variable X, a choice is made between X #=< M and X #> M, where M is the midpoint of the domain of X.
At most one option of each category can be specified, and an option must not occur repeatedly.
The order of solutions can be influenced with:
min(Expr)
max(Expr)
This generates solutions in ascending/descending order with respect to the evaluation of the arithmetic expression Expr. Labeling Vars must make Expr ground. If several such options are specified, they are interpreted from left to right, e.g.:
?- [X,Y] ins 10..20, labeling([max(X),min(Y)],[X,Y]).
This generates solutions in descending order of X, and for each binding of X, solutions are generated in ascending order of Y. To obtain the incomplete behaviour that other systems exhibit with "maximize(Expr)" and "minimize(Expr)", use once/1, e.g.:
once(labeling([max(Expr)], Vars))
Labeling is always complete, always terminates, and yields no redundant solutions.
all_different(+Vars)
Like all_distinct/1, but with weaker propagation.
all_distinct(+Vars).
True iff Vars are pairwise distinct. For example, all_distinct/1 can detect that not all variables can assume distinct values given the following domains:
?- maplist(in, Vs,
[1\/3..4, 1..2\/4, 1..2\/4, 1..3, 1..3, 1..6]),
all_distinct(Vs).
false.
nvalue(?N, +Vars).
True if N is the number of distinct values taken by Vars. Vars is a list of domain variables, and N is a domain variable. Can be thought of as a relaxed version of all_distinct/1.
sum(+Vars, +Rel, ?Expr)
The sum of elements of the list Vars is in relation Rel to Expr. Rel is one of #=, #=, #<, #>, #=< or #>=. For example:
?- [A,B,C] ins 0..sup, sum([A,B,C], #=, 100).
A in 0..100,
A+B+C#=100,
B in 0..100,
C in 0..100.
scalar_product(+Cs, +Vs, +Rel, ?Expr)
True iff the scalar product of Cs and Vs is in relation Rel to Expr. Cs is a list of integers, Vs is a list of variables and integers. Rel is #=, #=, #<, #>, #=< or #>=.
#>=(?X, ?Y)
Same as Y #=< X. When reasoning over integers, replace (>=)/2 by (#>=)/2 to obtain more general relations.
#=<(?X, ?Y)
The arithmetic expression X is less than or equal to Y. When reasoning over integers, replace (=<)/2 by (#=<)/2 to obtain more general relations.
#=(?X, ?Y)
The arithmetic expression X equals Y. When reasoning over integers, replace (is)/2
by (#=)/2
to obtain more general relations.
#\=(?X, ?Y)
The arithmetic expressions X and Y evaluate to distinct integers. When reasoning over integers, replace (==)/2 by (#=)/2 to obtain more general relations.
#>(?X, ?Y)
Same as Y #< X.
#<(?X, ?Y)
The arithmetic expression X is less than Y. When reasoning over integers, replace (<)/2
by (#<)/2
to obtain more general relations.
In addition to its regular use in tasks that require it, this constraint can also be useful to eliminate uninteresting symmetries from a problem. For example, all possible matches between pairs built from four players in total:
?- Vs = [A,B,C,D], Vs ins 1..4,
all_different(Vs),
A #< B, C #< D, A #< C,
findall(pair(A,B)-pair(C,D), label(Vs), Ms).
Ms = [ pair(1, 2)-pair(3, 4),
pair(1, 3)-pair(2, 4),
pair(1, 4)-pair(2, 3)].
#\(+Q)
The reifiable constraint Q does not hold. For example, to obtain the complement of a domain:
?- #\ X in -3..0\/10..80.
X in inf.. -4\/1..9\/81..sup.
#<==>(?P, ?Q)
P and Q are equivalent. For example:
?- X #= 4 #<==> B, X #\= 4.
B = 0,
X in inf..3\/5..sup.
The following example uses reified constraints to relate a list of finite domain variables to the number of occurrences of a given value:
vs_n_num(Vs, N, Num) :-
maplist(eq_b(N), Vs, Bs),
sum(Bs, #=, Num).
eq_b(X, Y, B) :- X #= Y #<==> B.
Sample queries and their results:
?- Vs = [X,Y,Z], Vs ins 0..1, vs_n_num(Vs, 4, Num).
Vs = [X, Y, Z],
Num = 0,
X in 0..1,
Y in 0..1,
Z in 0..1.
?- vs_n_num([X,Y,Z], 2, 3).
X = 2,
Y = 2,
Z = 2.
#==>(?P, ?Q)
P implies Q.
#<==(?P, ?Q)
Q implies P.
#/\(?P, ?Q)
P and Q hold.
#\/(?P, ?Q)
P or Q holds. For example, the sum of natural numbers below 1000 that are multiples of 3 or 5:
?- findall(N, (N mod 3 #= 0 #\/ N mod 5 #= 0, N in 0..999,
indomain(N)),
Ns),
sum(Ns, #=, Sum).
Ns = [0, 3, 5, 6, 9, 10, 12, 15, 18|...],
Sum = 233168.
#\(?P, ?Q)
Either P holds or Q holds, but not both.
lex_chain(+Lists)
Lists are lexicographically non-decreasing.
tuples_in(+Tuples, +Relation).
True iff all Tuples are elements of Relation. Each element of the list Tuples is a list of integers or finite domain variables. Relation is a list of lists of integers. Arbitrary finite relations, such as compatibility tables, can be modeled in this way. For example, if 1 is compatible with 2 and 5, and 4 is compatible with 0 and 3:
?- tuples_in([[X,Y]], [[1,2],[1,5],[4,0],[4,3]]), X = 4.
X = 4,
Y in 0\/3.
As another example, consider a train schedule represented as a list of quadruples, denoting departure and arrival places and times for each train. In the following program, Ps is a feasible journey of length 3 from A to D via trains that are part of the given schedule.
trains([[1,2,0,1],
[2,3,4,5],
[2,3,0,1],
[3,4,5,6],
[3,4,2,3],
[3,4,8,9]]).
threepath(A, D, Ps) :-
Ps = [[A,B,_T0,T1],[B,C,T2,T3],[C,D,T4,_T5]],
T2 #> T1,
T4 #> T3,
trains(Ts),
tuples_in(Ps, Ts).
In this example, the unique solution is found without labeling:
?- threepath(1, 4, Ps).
Ps = [[1, 2, 0, 1], [2, 3, 4, 5], [3, 4, 8, 9]].
serialized(+Starts, +Durations)
Describes a set of non-overlapping tasks. Starts = [S1,...,Sn], is a list of variables or integers, Durations = [D1,...,Dn] is a list of non-negative integers. Constrains Starts and Durations to denote a set of non-overlapping tasks, i.e.: Si + Di =< Sj or Sj + Dj =< Si for all 1 =< i < j =< n. Example:
?- length(Vs, 3),
Vs ins 0..3,
serialized(Vs, [1,2,3]),
label(Vs).
Vs = [0,1,3]
; Vs = [2,0,3]
; false.
@see Dorndorf et al. 2000, "Constraint Propagation Techniques for the Disjunctive Scheduling Problem"
element(?N, +Vs, ?V)
The N-th element of the list of finite domain variables Vs is V. Analogous to nth1/3.
global_cardinality(+Vs, +Pairs)
Global Cardinality constraint. Equivalent to global_cardinality(Vs, Pairs, [])
. Example:
?- Vs = [_,_,_], global_cardinality(Vs, [1-2,3-_]), label(Vs).
Vs = [1,1,3]
; Vs = [1,3,1]
; Vs = [3,1,1]
; false.
global_cardinality(+Vs, +Pairs, +Options)
Global Cardinality constraint. Vs is a list of finite domain variables, Pairs is a list of Key-Num pairs, where Key is an integer and Num is a finite domain variable. The constraint holds iff each V in Vs is equal to some key, and for each Key-Num pair in Pairs, the number of occurrences of Key in Vs is Num. Options is a list of options. Supported options are:
consistency(value)
A weaker form of consistency is used.
cost(Cost, Matrix)
Matrix is a list of rows, one for each variable, in the order they occur in Vs. Each of these rows is a list of integers, one for each key, in the order these keys occur in Pairs. When variable v_i is assigned the value of key k_j, then the associated cost is Matrix_{ij}. Cost is the sum of all costs.
circuit(+Vs)
True iff the list Vs of finite domain variables induces a Hamiltonian circuit. The k-th element of Vs denotes the successor of node k. Node indexing starts with 1. Examples:
?- length(Vs, _), circuit(Vs), label(Vs).
Vs = []
; Vs = [1]
; Vs = [2,1]
; Vs = [2,3,1]
; Vs = [3,1,2]
; Vs = [2,3,4,1]
; ... .
cumulative(+Tasks)
Equivalent to cumulative(Tasks, [limit(1)]).
cumulative(+Tasks, +Options)
Schedule with a limited resource. Tasks is a list of tasks, each of the form task(Si, Di, Ei, Ci, Ti). Si denotes the start time, Di the positive duration, Ei the end time, Ci the non-negative resource consumption, and Ti the task identifier. Each of these arguments must be a finite domain variable with bounded domain, or an integer. The constraint holds iff at each time slot during the start and end of each task, the total resource consumption of all tasks running at that time does not exceed the global resource limit. Options is a list of options. Currently, the only supported option is:
limit(L) The integer L is the global resource limit. Default is 1.
For example, given the following predicate that relates three tasks of durations 2 and 3 to a list containing their starting times:
tasks_starts(Tasks, [S1,S2,S3]) :-
Tasks = [task(S1,3,_,1,_),
task(S2,2,_,1,_),
task(S3,2,_,1,_)].
We can use cumulative/2 as follows, and obtain a schedule:
?- tasks_starts(Tasks, Starts), Starts ins 0..10,
cumulative(Tasks, [limit(2)]), label(Starts).
Tasks = [task(0, 3, 3, 1, _G36), task(0, 2, 2, 1, _G45), ...],
Starts = [0, 0, 2] .
disjoint2(+Rectangles)
True iff Rectangles are not overlapping. Rectangles is a list of terms of the form F(Xi, Wi, Yi, Hi), where F is any functor, and the arguments are finite domain variables or integers that denote, respectively, the X coordinate, width, Y coordinate and height of each rectangle.
automaton(+Vs, +Nodes, +Arcs)
Describes a list of finite domain variables with a finite automaton. Equivalent to automaton(Vs, _, Vs, Nodes, Arcs, [], [], _), a common use case of automaton/8. In the following example, a list of binary finite domain variables is constrained to contain at least two consecutive ones:
two_consecutive_ones(Vs) :-
automaton(Vs, [source(a),sink(c)],
[arc(a,0,a), arc(a,1,b),
arc(b,0,a), arc(b,1,c),
arc(c,0,c), arc(c,1,c)]).
Example query:
?- length(Vs, 3), two_consecutive_ones(Vs), label(Vs).
Vs = [0,1,1]
; Vs = [1,1,0]
; Vs = [1,1,1]
; false.
automaton(+Sequence, ?Template, +Signature, +Nodes, +Arcs, +Counters, +Initials, ?Finals)
Describes a list of finite domain variables with a finite automaton. True iff the finite automaton induced by Nodes and Arcs (extended with Counters) accepts Signature. Sequence is a list of terms, all of the same shape. Additional constraints must link Sequence to Signature, if necessary. Nodes is a list of source(Node) and sink(Node) terms. Arcs is a list of arc(Node,Integer,Node) and arc(Node,Integer,Node,Exprs) terms that denote the automaton's transitions. Each node is represented by an arbitrary term. Transitions that are not mentioned go to an implicit failure node. Exprs
is a list of arithmetic expressions, of the same length as Counters. In each expression, variables occurring in Counters symbolically refer to previous counter values, and variables occurring in Template refer to the current element of Sequence. When a transition containing arithmetic expressions is taken, each counter is updated according to the result of the corresponding expression. When a transition without arithmetic expressions is taken, all counters remain unchanged. Counters is a list of variables. Initials is a list of finite domain variables or integers denoting, in the same order, the initial value of each counter. These values are related to Finals according to the arithmetic expressions of the taken transitions.
The following example is taken from Beldiceanu, Carlsson, Debruyne and Petit: "Reformulation of Global Constraints Based on Constraints Checkers", Constraints 10(4), pp 339-362 (2005). It relates a sequence of integers and finite domain variables to its number of inflexions, which are switches between strictly ascending and strictly descending subsequences:
sequence_inflexions(Vs, N) :-
variables_signature(Vs, Sigs),
automaton(Sigs, _, Sigs,
[source(s),sink(i),sink(j),sink(s)],
[arc(s,0,s), arc(s,1,j), arc(s,2,i),
arc(i,0,i), arc(i,1,j,[C+1]), arc(i,2,i),
arc(j,0,j), arc(j,1,j),
arc(j,2,i,[C+1])],
[C], [0], [N]).
variables_signature([], []).
variables_signature([V|Vs], Sigs) :-
variables_signature_(Vs, V, Sigs).
variables_signature_([], _, []).
variables_signature_([V|Vs], Prev, [S|Sigs]) :-
V #= Prev #<==> S #= 0,
Prev #< V #<==> S #= 1,
Prev #> V #<==> S #= 2,
variables_signature_(Vs, V, Sigs).
Example queries:
?- sequence_inflexions([1,2,3,3,2,1,3,0], N).
N = 3.
?- length(Ls, 5), Ls ins 0..1,
sequence_inflexions(Ls, 3), label(Ls).
Ls = [0, 1, 0, 1, 0] ;
Ls = [1, 0, 1, 0, 1].
zcompare(?Order, ?A, ?B)
Analogous to compare/3, with finite domain variables A and B.
This predicate allows you to make several predicates over integers deterministic while preserving their generality and completeness. For example:
n_factorial(N, F) :-
zcompare(C, N, 0),
n_factorial_(C, N, F).
n_factorial_(=, _, 1).
n_factorial_(>, N, F) :-
F #= F0*N, N1 #= N - 1,
n_factorial(N1, F0).
This version is deterministic if the first argument is instantiated, because first argument indexing can distinguish the two different clauses:
?- n_factorial(30, F).
F = 265252859812191058636308480000000.
The predicate can still be used in all directions, including the most general query:
?- n_factorial(N, F).
N = 0, F = 1
; N = 1, F = 1
; N = 2, F = 2
; ... .
chain(+Relation, +Zs)
Zs form a chain with respect to Relation. Zs is a list of finite domain variables that are a chain with respect to the partial order Relation, in the order they appear in the list. Relation must be #=, #=<, #>=, #< or #>. For example:
?- chain(#>=, [X,Y,Z]).
X#>=Y,
Y#>=Z.
fd_var(+Var)
True iff Var is a CLP(ℤ) variable.
fd_inf(+Var, -Inf)
Inf is the infimum of the current domain of Var.
fd_sup(+Var, -Sup)
Sup is the supremum of the current domain of Var.
fd_size(+Var, -Size)
Size is the number of elements of the current domain of Var, or the atom sup if the domain is unbounded.
fd_dom(+Var, -Dom)
Dom is the current domain (see (in)/2
) of Var. This predicate is useful if you want to reason about domains. It is not needed if you only want to display remaining domains; instead, separate your model from the search part and let the toplevel display this information via residual goals.
For example, to implement a custom labeling strategy, you may need to inspect the current domain of a finite domain variable. With the following code, you can convert a finite domain to a list of integers:
dom_integers(D, Is) :- phrase(dom_integers_(D), Is).
dom_integers_(I) --> { integer(I) }, [I].
dom_integers_(L..U) --> { numlist(L, U, Is) }, Is.
dom_integers_(D1\/D2) --> dom_integers_(D1), dom_integers_(D2).
Example:
?- X in 1..5, X #\= 4, fd_dom(X, D), dom_integers(D, Is).
D = 1..3\/5,
Is = [1,2,3,5],
X in 1..3\/5.